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0=6.5+6x-4.9x^2
We move all terms to the left:
0-(6.5+6x-4.9x^2)=0
We add all the numbers together, and all the variables
-(6.5+6x-4.9x^2)=0
We get rid of parentheses
4.9x^2-6x-6.5=0
a = 4.9; b = -6; c = -6.5;
Δ = b2-4ac
Δ = -62-4·4.9·(-6.5)
Δ = 163.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-\sqrt{163.4}}{2*4.9}=\frac{6-\sqrt{163.4}}{9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+\sqrt{163.4}}{2*4.9}=\frac{6+\sqrt{163.4}}{9.8} $
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